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Well, for all you breeding fanatics, it appears like it is now possible to chain-breed Pokémon to have perfect IVs and the correct nature. You'll need to have an Everstone, Destiny Knot, all of the Power items, and a bunch of Ditto, though, and they must be obtained through the gimmicky Friend Safari. (This would be infinitely easier if you didn't have to actually become 3DS friends, as I could just share FCs of games with Ditto.)
Anyway, I'm not sure of the exact process, but you have to use the IV checker in Kiloude City to figure out which Ditto have which perfect IVs, then breed your desired Pokémon with them in the correct order with the correct items attached. In the end, you'll be able to relatively easily obtain a perfect 31 spread with the correct nature and ability, and extremely easily obtain a near-perfect spread with the correct nature and ability.
2 – TurtwigX, Ditto616|
Well, I've got a few perfect Zorua (Modest with 31/*/31/31/31/31), as well as few others with five perfect stats.
Now to use those to get some perfect Eevee. |
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Would you be willing to trade for a Modest Zorua? I am trying to get an excellent Eevee that knows Wish and Zorua would greatly speed up the process. Is there anything in particular that you are looking for The majority of my good Pokemon are still on my Gen. 5 games, so I would be willing to trade between those games. I have EV-trained Pokemon aplenty.
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Is there a step by step process someone can run me by if I don't have a perfect Ditto? I don't have a friend with it in their Safari, and even so I'd feel like a bad person if I added them for that reason alone. I'll probably have to go GTS hunting or something until I can transfer the Ditto I already have.
I don't have a perfect Ditto (or a friend with them in their safari). I just caught a few of a related Pokémon from the same egg group and passed the IVs over. You have to abuse the Destiny Knot and Everstone, though. Pretty much, keep the Destiny Knot with the Pokémon with more desirable stats and shoot for having both males and females with many desirable stats. It's messy and may take a long time if the Pokémon have an annoying ratio like Eevee's and Zorua's 7-males-to-1-female. Good luck!
1 – TurtwigXI not only have a perfect Zorua, but I have three perfect females and a perfect male, which means I can easily multiply them with a chance of 37 in 192 of getting a perfect egg.
Pity there's no reason to get a shiny perfect Zorua, though. Zoroark is arguably the most useless shiny to use in battle.
(It's arguable because Ditto is about equally useless as a shiny.) I do have a legitimate shiny Zorua in Gen V, I believe. Its stats are probably laughable, though. 
1 – TurtwigXYeah, the IV guy is annoying. Even if you had something amazing like 30/29/29/29/29/29, he'd still only comment on HP because it's the only one with that value. The only way to get him to make a comment on multiple stats is for them to have the same value (and be the highest).
The IV guy doesn't exactly tell you anything. He gives you the average of your IVs by rating their potential "Decent, good, outstanding all around" and then he tells you your highest IV(s) and how high they are. If it can't get any better or can't be beat as it apparently is in this generation, then the value is 31.
In short, use an IV calculator.
Well, thinking about it a little more... When he say's "stats like those can't be beat" is he talking about the one(s) he pointed out or the other stats? Yeah, I actually have no idea what the Pokemon's potential has anything to do with the actual IV spread.
IV calculator is online only, though. D: When I play my game, I play MAH GAME.
If something "can't be beat" I'm assuming it's the highest, and also the one he pointed out, no? I don't check IVs, and I haven't checked anything from the Friend Safari yet. I'll do that after I feel like catching Mewtwo.
Well if you wanna be that stubborn and don't want a very accurate read on your IVs go ahead~
That's right, but I was just muddying things up on myself confusing his words and stuff.
Pff, I read them. Everytime I catch a legendary and soft-reset, I memorize which neutral stats are highest and read the description it has. This lets me know when a particular stat IV is relatively good or not. Get that tech out! ![]()
2 – TurtwigX, Cat333Pokémon|
I'm too impatient to breed for perfect IVs, even now with how easy they've went and made it. "Good enough" works among the people I usually battle, in the lower-intensity levels of Pokémon competition.
Does anyone else half-expect them to delete IVs altogether someday? |
Welp, I bred another 31/31/31/31/31/31 Pokémon, this time a Furfrou.
What am I doing with my life.
1 – JDxImpetusHow long has anyone breed a certain species in order to obtain your "perfect" Pokemon? Starting with the longest time.
I just got done breeding for a female Eevee with Anticipation. Took me about 5 hours. GameFreak, why did you make the female percentage rate so low?! D: Has awesome IVs, though, so I'm good on that perspective.
I finally did it: a 6 IV Pokémon. The 5 IV father had 31/*/31/31/31, and the 2 IV mother had */*/*/31/31/*. That's a 1 in 1,536 chance of occurring, I believe. It only took four eggs, too. ![]()
2 – Alakazamaster, TwiggyThe Destiny Knot forces the breeding procedure to pass down five IVs from the parents (instead of the usual three). It does not matter which parent holds the item; it has the same effect either way. They also do not stack, as both items would cause the same effect, making the second one redundant. It selects one of the six stats not to pass down and randomly gives it a value between 0 and 31. After it chooses which one not to pass down, the other five are randomly selected between either the mother or the father for which one passes down the value.
Let's look at an example and assume two 4 IV parents:
Mother: 31/31/7/16/31/31
Father: 26/31/31/31/2/31
Let's assume one is holding an Everstone and passing the correct nature along, while the other is holding a Destiny Knot. Let's also assume the ability is irrelevant.
If we want a child with the Adamant nature to become a physical sweeper, the target IVs are as follows: 31/31/31/*/31/31, where * means any value is acceptable. This means that the mother must pass down its 31s in HP and Special Defense, the father must pass down its 31 in Defense, and either parent can pass down Attack and Speed. Special Attack must be the one selected to be not passed down. So, let's look at this mathematically. The odds of selecting Special Attack not to pass down are 1 in 6. For the mother and father to each pass down the correct stats each of them only has, the odds are 1 in 2 x 2 x 2, or 8. The odds of getting a perfect 5-or-more IV child with the correct stat distribution are 1 in 6 x 8, or 48. On average, you must hatch 48 eggs to get a perfect child using those two parents.
If you want a 6 IV child from those parents, things get a little more complicated. First, let's look at how many different ways stats can be pulled. (This will also give us the odds of getting a 6 IV child assuming one 5 IV parent and one 0 IV parent.) 6 choices for the stat not to be selected, 2^6 (that's 64) choices for which parent will pass down each stat, and 32 choices for the remaining stat. Of these 6 x 64 x 32 = 12,288 permutations, how many result in a 6 IV child? The remaining stat must always be a 31, but because both parents cover all six stats, it doesn't matter which one it is, so that's a 32. Four stats must pass from the correct parents, so that's a 2^4 = 16. 16 x 32 = 512, so the odds are 1 in 512 that you'll get a 6 IV child with those parents. (There are 12,288/512 = 24 possible ways that it could be done.)
Now that I've explained the math behind that, let's look at your specific example. Again, we're going to ignore ability and presume you have the correct nature on one parent. This means both parents have 31/31/31/31/31/31. This time, it doesn't matter which stats are chosen to be brought to the child; they will always be 31s. However, the last stat is still randomized, so the odds of getting a perfect child are 1 in 32. How about something easier: the odds of getting a 5-or-more IV child with the correct IV missing are a lovely 1 in 6.
Bonus question: how hard would it be to get a 6 IV parent without the Destiny Knot, even with two 6 IV parents? 1 in 32^3 = 32,768. It's not worth trying at that point.
Second bonus question: what are the odds of finding a wild 6 IV female Eevee with the correct nature, and ability (let's ignore the hidden one)--and shiny--in Pokémon X? 32^6 for the IVs, 8 for the gender, 2 for the ability, 25 for the nature, and 4,096 for the shininess. 1 in 1,759,218,604,441,600. Good luck. 
3 – TurtwigX, Alakazamaster, Twiggy|
The Destiny Knot forces the breeding procedure to pass down five IVs from the parents (instead of the usual three). It does not matter which parent holds the item; it has the same effect either way. They also do not stack, as both items would cause the same effect, making the second one redundant. It selects one of the six stats not to pass down and randomly gives it a value between 0 and 31. After it chooses which one not to pass down, the other five are randomly selected between either the mother or the father for which one passes down the value.
Let's look at an example and assume two 4 IV parents: Mother: 31/31/7/16/31/31 Father: 26/31/31/31/2/31 Let's assume one is holding an Everstone and passing the correct nature along, while the other is holding a Destiny Knot. Let's also assume the ability is irrelevant. If we want a child with the Adamant nature to become a physical sweeper, the target IVs are as follows: 31/31/31/*/31/31, where * means any value is acceptable. This means that the mother must pass down its 31s in HP and Special Defense, the father must pass down its 31 in Defense, and either parent can pass down Attack and Speed. Special Attack must be the one selected to be not passed down. So, let's look at this mathematically. The odds of selecting Special Attack not to pass down are 1 in 6. For the mother and father to each pass down the correct stats each of them only has, the odds are 1 in 2 x 2 x 2, or 8. The odds of getting a perfect 5-or-more IV child with the correct stat distribution are 1 in 6 x 8, or 48. On average, you must hatch 48 eggs to get a perfect child using those two parents. If you want a 6 IV child from those parents, things get a little more complicated. First, let's look at how many different ways stats can be pulled. (This will also give us the odds of getting a 6 IV child assuming one 5 IV parent and one 0 IV parent.) 6 choices for the stat not to be selected, 2^6 (that's 64) choices for which parent will pass down each stat, and 32 choices for the remaining stat. Of these 6 x 64 x 32 = 12,288 permutations, how many result in a 6 IV child? The remaining stat must always be a 31, but because both parents cover all six stats, it doesn't matter which one it is, so that's a 32. Four stats must pass from the correct parents, so that's a 2^4 = 16. 16 x 32 = 512, so the odds are 1 in 512 that you'll get a 6 IV child with those parents. (There are 12,288/512 = 24 possible ways that it could be done.) Now that I've explained the math behind that, let's look at your specific example. Again, we're going to ignore ability and presume you have the correct nature on one parent. This means both parents have 31/31/31/31/31/31. This time, it doesn't matter which stats are chosen to be brought to the child; they will always be 31s. However, the last stat is still randomized, so the odds of getting a perfect child are 1 in 32. How about something easier: the odds of getting a 5-or-more IV child with the correct IV missing are a lovely 1 in 6. Bonus question: how hard would it be to get a 6 IV parent without the Destiny Knot, even with two 6 IV parents? 1 in 32^3 = 32,768. It's not worth trying at that point. Second bonus question: what are the odds of finding a wild 6 IV female Eevee with the correct nature, and ability (let's ignore the hidden one)--and shiny--in Pokémon X? 32^6 for the IVs, 8 for the gender, 2 for the ability, 25 for the nature, and 4,096 for the shininess. 1 in 1,759,218,604,441,600. Good luck. ![]() |